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(D) The reaction of benzyl phenyl ether with $HI$ involves the protonation of the ether oxygen atom. Following protonation,the $C-O$ bond between the

Vedclass · Accepted Answer

$A = C_6H_5CH_2I$ and $B = C_6H_5OH$

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(D) The reaction of benzyl phenyl ether with $HI$ involves the protonation of the ether oxygen atom. Following protonation,the $C-O$ bond between the benzyl carbon and the oxygen atom breaks to form a stable benzyl carbocation $(C_6H_5CH_2^+)$ and phenol $(C_6H_5OH)$. The benzyl carbocation is stabilized by resonance with the phenyl ring. Finally,the iodide ion $(I^-)$ attacks the benzyl carbocation to form benzyl iodide $(C_6H_5CH_2I)$. Thus,the products are $A = C_6H_5CH_2I$ and $B = C_6H_5OH$.

Consider the following reaction. Identify products $A$ and $B$ :-

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